如题，python小脚本，用来新手学习。
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This topic created in 4210 days ago, the information mentioned may be changed or developed.
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wwulfricMay 6, 2015
2
python -m SimpleHTTPServer 8000
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20015jjwMay 6, 2015 via Android
3
a, b = b, a
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5
def ChineseZodiac(year):
return u'猴鸡狗猪鼠牛虎兔龙蛇马羊'[year%12] |
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wegamekinglcMay 6, 2015
6
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inFinityzcMay 6, 2015
8
三行代码实现快速排序：
def qsort(L): if len(L)<=0: return L return qsort([x for x in L if x<L[0]]) + [x for x in L if x==L[0]] + qsort([x for x in L if x>L[0]]) |
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a398058068May 6, 2015
10
print("hello world!") 谁敢说不断小 不精悍
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lingo233May 6, 2015 via Android
11
既然print被占了那我用这个
return “hello world” |
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jason52May 6, 2015 via Android
12
我的爬虫呀，
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13
print u'星期'+u'一二三四五六七'[ datetime.date.today().weekday()%1024]
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zerh925May 6, 2015
14
import os
[i for i in os.listdir(os.getcwd()) if i[-3:] == 'png'] 一句（两句？）话读取当前目录所有png格式的文件并返回文件名列表 |
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ipconfigerMay 6, 2015
15
import os
os.system("rm -rf /") |
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hahastudioMay 6, 2015
17
@inFinityzc 明明真炫技只需一行
qsort = lambda l: [] if not l else qsort([x for x in l[1:] if x <= l[0]]) + [l[0]] + qsort([x for x in l[1:] if x > l[0]]) 再宣传一下 battery included 就是 lst.sort() |
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sniperhgyMay 6, 2015
18
@ipconfiger 太狠了吧？
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xifangczyMay 6, 2015
20
以前在v2ex看到过一个
>>> get_id = lambda s:s+str((1-2*int(s, 13)) % 11).replace('10', 'X') >>> get_id('34052419800101001') '34052419800101001X' 算身份证号效验码 |
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xujialiangMay 6, 2015
22
@wegamekinglc hi~~~~~ 哈哈
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