有一个由 NSDictionary 组成的 NSArray，现在希望这个 array 中元素按照 dictionary 的某个 NSNumber 属性的大小来排倒序，应该如何实现呢？
iOS 开发实用技术导航
NSHipster 中文版
› http://nshipster.cn/
cocos2d 开源 2D 游戏引擎
› http://www.cocos2d-iphone.org/
CocoaPods
› http://cocoapods.org/
Google Analytics for Mobile 统计解决方案
› http://code.google.com/mobile/analytics/
WWDC
› https://developer.apple.com/wwdc/
Design Guides and Resources
› https://developer.apple.com/design/
Transcripts of WWDC sessions
› http://asciiwwdc.com
Cocoa with Love
› http://cocoawithlove.com/
Cocoa Dev Central
› http://cocoadevcentral.com/
NSHipster
› http://nshipster.com/
Style Guides
› Google Objective-C Style Guide
› NYTimes Objective-C Style Guide
Useful Tools and Services
› Charles Web Debugging Proxy
› Smore
This topic created in 5364 days ago, the information mentioned may be changed or developed.
 |
1
linlinqi Jan 29, 2012
用sortedArrayUsingComparator是不是可以呢
<pre> NSArray *sortedArray; sortedArray = [drinkDetails sortedArrayUsingComparator:^(id a, id b) { NSDate *first = [(Person*)a birthDate]; NSDate *second = [(Person*)b birthDate]; return [first compare:second]; }]; </pre> 见 http://stackoverflow.com/questions/805547/how-to-sort-an-nsmutablearray-with-custom-objects-in-it |
 |
2
lizdo Jan 29, 2012
楼上的改成NSNumber *first = [a objectForKey:xxx];就可以了
这种问题的确StackOverflow比较无敌 |
Select Language