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vcent
V2EX  ›  Python

Python re.findall 匹配的到 re.sub 却替换不掉呢？

  •   
  •   vcent · Apr 18, 2019 · 2911 views
    This topic created in 2721 days ago, the information mentioned may be changed or developed.

    这段文本

    In [6]: re.findall("<!--.*-->",aa,re.S|re.M)   #这样匹配的到
Out[6]: ['<!--\ngoogle_ad_client = "pub-7133395778201029";\ngoogle_ad_width = 468;\ngoogle_ad_height = 60;\ngoogle_ad_format = "468x60_as";\ngoogle_ad_type = "image";\ngoogle_ad_channel = "";\n//-->']

    In [8]: re.sub("<!--.*-->","",aa,re.S|re.M)  #这样替换不掉呢
Out[8]: '<!--\ngoogle_ad_client = "pub-7133395778201029";\ngoogle_ad_width = 468;\ngoogle_ad_height = 60;\ngoogle_ad_format = "468x60_as";\ngoogle_ad_type = "image";\ngoogle_ad_channel = "";\n//-->'

    一直是这么写的没毛病 啊 为啥这次不行了呢

  • x60_as
  • image
  • nda
  • SUB
    4 replies  •  2019-04-19 08:30:30 +08:00
    kcnscrew
        1
    kcnscrew  
       Apr 18, 2019
    def findall(pattern, string, flags=0)
    def sub(pattern, repl, string, count=0, flags=0)
    yemoluo
        2
    yemoluo  
       Apr 19, 2019 via iPhone
    大哥，参数顺序错了
    vcent
        3
    vcent  
    OP
       Apr 19, 2019
    @kcnscrew 多谢 已解决
    vcent
        4
    vcent  
    OP
       Apr 19, 2019
    @GTim 多谢 已解决
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