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guanzhangzhang

切片去掉重复的部分,求高效思路

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  •   guanzhangzhang ·
    zhangguanzhang · Jun 10, 2019 · 3393 views
    This topic created in 2706 days ago, the information mentioned may be changed or developed.
    例如 1 2 3, 2 3 4 => 1 4; 1 2 3 1, 2 3 4=> 1 4
    想到的是利用 map 的 key 唯一性,map[type]struct{}
    5 replies  •  2019-06-11 15:18:28 +08:00
    aeli
    aeli
    Jun 10, 2019
    1
    如果只是 int 型,位运算即可
    CEBBCAT
    CEBBCAT
    Jun 11, 2019 via Android
    2
    楼主这文字描述能力略差啊,我重新诠释一下你看对不对:
    现有两个数集,称作 a b,先将各自转化为集合,再求 a-b
    www5070504
    www5070504
    Jun 11, 2019
    3
    没看出来跟切片有啥联系啊。。
    guanzhangzhang
    guanzhangzhang
    OP
    Jun 11, 2019
    4
    @www5070504 a:= []string{"1","2","3"} b :=[]string{"2","3","4"}, result := []string{"1","4"}
    @aeli
    leon0903
    leon0903
    Jun 11, 2019
    5
    直接用 map 吧 不要折腾了。 我就是用的 map
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